31 lines
577 B
Python
31 lines
577 B
Python
#!/usr/bin/env python3
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from Cryptotools.Groups.cyclic import Cyclic
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from math import log, ceil
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def ope(a, b, n):
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return (a ** b) % n
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n = 7919
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group = list()
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for x in range(1, n):
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group.append(x)
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cyclic = Cyclic(group, n, ope)
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g = cyclic.getPrimitiveRoot()
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print(f"g: {g}")
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secretKey = 4057
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publicKey = ope(g, secretKey, n)
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print(f"Public key: {publicKey}")
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# Now, we need to find the secret key based on the DLP
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for x in range(1, n):
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l = log(x, g)
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h = ceil(g ** l)
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if ope(g, h, n) == publicKey:
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print(f"Secret key found: {h}")
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break
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